LN2 space (Magnet Shield) Heat Load
Formula: 
(Reference: http://twist.phys.virginia.edu:8081/General/69)
Duration:
10/24/2022 from 04:00 to 10:00 (6 hrs) [ Used the formula from elog #65 for LN2 volume]
Initial LN2 volume = 112.858 L
Final LN2 volume = 111.102 L
Volume difference = 1.75594 L
LN2 density = 0.807 kg/L
Therefore, LN2 mass difference in boiloff = 1.75594 L x 0.807 kg/L = 1.417 kg
Latent Heat of LN2 = 1.992 x 10^5 J /kg
Heat from boiloff = 1.992 x 10^5 J /kg x 1.417 kg = 2.82 x 10^5 J
Duration in seconds = 6 x 60 x 60 s
Heat Load in Watts = 2.82 x 10^5 J / 7200s = 13.0683 W
LHe space Heat Load
Zoomed sections to calculate the heat-load
(Initial) (Final)
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Volume difference in 24hrs = 112.355 – 86.590 L = 25.76 L 
That is about ~ 0.7 J/s (W), and this is with LN2 in the shield.
Heat-load for a given 'magnet outlet flow' (in V slm)
(Note: Temperatures in the magnet have to be approximately unchanged during this flow measurement)